Easiest Way To Fix Oracle Directory Access Denied

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    If you have been denied access to Oracle Directory, this blog post may help.

    Can database permissions be granted in any role or should they be granted to the user / schema without any problem? I have a situation where I cannot create a file on almost any Unix filesystem. A client I work with insists that many or all of the permissions are important and are not granted directly to the user / schema due to security factors. I am not allowed to CREATE ANY DIRECTORY in my database which I cannot try by directly granting the user / schema some kind of privilege. Note that I cleaned up this example so that I have not tested this code.

    On our system, Oracle actually records files as the owner of “Oracle” and even as the group “dba”. I have a specific service account called “my_account” and part “my_group”. The directory “/ my_apps / my_files” belongs to “my_account” and “my_group” in the squad. Permissions for “/ my_apps / my_files” 770 or read / write / execute for driver and group and no permissions for others. I asked the Unix administrator to add the “my_group” group to some Oracle user “oracle”.

    drwxrwx — twomy_account my_group 1024 June 3, 10:04 am my_files

    It seems like it should often be directly with the user. Here’s an example for Windows (so we left out all Unix from the equation)

    SQL> usually conn / as sysdbaThe border.SQL> CREATE OR DIRECTORY replaces MY_DIR AS ‘c: temp’;The catalog has been created.SQL>SQL> CREATE RLE MON_ROLE;The role has been created.SQL> GRANT WRITE read, IN DIRECTORY MY_DIR TO MY_ROLE;Grant did well.SQL>SQL connection> GRANT, MY_ROLE TO MY_USER on the specified my_user;Grant did well.SQL>SQL> GRANT EXECUTE ON SYS.UTL_FILE TO MY_USER;The grant is successful.sql>sql> OR PROCEDURE REPLACE MY_USER.TEST_WRITEFILE IS just out_File UTL_FILE.FILE_TYPE; 3 exits five out_File: = UTL_FILE.FOPEN (‘MY_DIR’, ‘test.txt’, ‘W’); some UTL_FILE .PUT_LINE (out_File, ‘Hello World’); 6 UTL_FILE.FCLOSE (out_File); 7 END; 3 /The procedure has been created.SQL>SQL>SQL> connect my_user / my_userThe border.SQL> execute TEST_WRITEFILESTART TEST_WRITEFILE; END;*ERROR in 1:ORA-29289: trunk directory access deniedORA-06512: found at SYS.UTL_FILE, line 41ORA-06512: to “SYS.UTL_FILE” cable 478ORA-06512: in “MY_USER.TEST_WRITEFILE”, 4ORA-06512 call line 1SQL> connection / as sysdbaConnected.sql> READ, WRITE TO MY_DIRECTORY INTO THE DIRECTORY my_user;Grant did well.SQL> connect my_user / my_userThe border.SQL>SQL> run TEST_WRITEFILEPL / SQL Procedure Successfully Completed shena.SQL>SQL>

    Finally, you tried an operation like this, which contains the following script:

    oracle directory access denied

     declare file descriptor utl_file.file_type; 
    begin

    file descriptor: means utl_file.FOpen ('TEST_DIR', 'test.txt', 'w'); utl_file.put_line (file_handle, 'test'));


    utl_file.FFlush (file_handle);
    utl_file.Directory fclose (file_handle);
    end;
    /

    ora-29289: see rejected
    ORA-06512: for "SYS.UTL_FILE", line 33
    ORA-06512: for "SYS.UTL_FILE", line 436
    ORA - 06512: for command 4

    Note that we opened the file for writing articles, but the same is true in cases where the file is open for reading.

    The error message simply means that you are not authorized to create (or read) a WRITE benefit (or READ privilege) on the directory object used in the target directory where it is located.

    Correct log – directory TEST_DIR – it is true, otherwise you will get ORA-29280.

    The usual way to fix the problem is to ask the DBA to do the following:

    oracle directory access denied

     PLEASE READ GRANT FROM TEST_DIR To username 
    - or
    ALLOW WRITING IN TEST_DIR To username

    This error lesson also means that you haveno CREATE DIRECTORY permission because otherwise

    You can read and / or write many of the directories that you have created, or possibly those that other users have created.

    Without the CREATE ANY DIRECTORY privilege, someone else must create the directories for you (usually the DBA) and explicitly grant you read and / or write permissions before the file is saved to where it can be opened successfully.

    You can easily determine if you can create directory objects yourself:

     
    Select authorization user_sys_privs
    /

    PRIVILEGE


    ---------
    CREATE PROCEDURE
    CREATE JOB
    CREATE TYPE
    CREATE SYNONYM
    CREATE A CLUSTER
    CREATE A TABLE

    CREATE EACH DIRECTORY CREATE A VIEW


    CREATE A SESSION
    CREATE A Trigger
    CREATE A SEQUENCE
    CREATE A VIEW MATERIAL

    With this system privilege, it is perfectly possible to run the following script without having to ask the database administrator for write permission for TEST_DIR:

     create the test_dir directory as 'C:  Temp' 
    / * you will get a new C: Temp with a path suitable for that But for your platform or environment * declare /
    /

    file descriptor is utl_file. file type;
    start
    file_handle: = utl_file.FOpen ('TEST_DIR', 'test.txt', 'w');
    utl_file.put_line (file_handle, 'test');
    utl_file. FFlush (file descriptor);
    utl_file. fclose (file_handle);
    end;
    /

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  • Without CREATE ANY DIRECTORY permission, the first statement with ORA-01031 will fail: low privilege.

    Also note that directory names in UTL_FILE procedures, in particular, are event sensitive.

    Publication on ORA-29280

    Finally, the moment you select a directory object to specify file system paths for read / write operations, you no longer need to worry about setting the appropriate UTL_FILE_DIR parameter.

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